This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1891 Excerpt: ...the truss loaded at the upper apex with 2 tons, giving vertical reactions of 1 ton each, with a supposed perfect roller under one end. The stress under this load in bar CD will be called s, in bars CB or BD s2, in bars AC or AD %, and in bar AB st, the bars symmetrical with respect to the center having the same stress. ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1891 Excerpt: ...the truss loaded at the upper apex with 2 tons, giving vertical reactions of 1 ton each, with a supposed perfect roller under one end. The stress under this load in bar CD will be called s, in bars CB or BD s2, in bars AC or AD %, and in bar AB st, the bars symmetrical with respect to the center having the same stress. Then regarding all stresses as tensions, we can deduce the following equations by noting that the sum of the horizontal and vertical components of the forces acting at C are separately equal to zero, and by balancing the vertical components of the stresses in the bars meeting at B..,500 1000.... 1 + rn8-2 + iii = 0-(1 From these three equations we derive: 500. rfs, 500 1118 1414 2 236 1000-jfe4 1000 S 1 118 S.'-ds2--1118 We have thus expressed slt -j, s4, in terms of s2, though any other bar than BC could have been selected as the superfluous bar with equal propriety, the ease of elimination being the chief thing to consider. Now, if for simplicity, we regard all the bars as having the same modulus of elasticity and cross-section, we have the total elastic work of deformation after strain, for all the bars of the truss, L=.2r2ai s'2 + 2a2-2 + 23 %2 + Gi 2' which must be a minimum; therefore putting its first differential coefficient, with respect to s2, equal to zero, we have, n Ai,, ds, ds. 2a, -l--+ 2a, -, + 2-3 H- + a = o On substituting the above values for sl t $$, s-r-, ----, --, we 'IS i-JS.i '. IS. readily deduce from the resulting equation of the first degree as to -j, s2 =--.39 tons, or.39 tons compression, whence, substituting in the above values for s3, s4, we find, sl = + 1.17, -3 =--1.17, s4 =--0.35. For span invariable (no roller) the term 2-j s,2 drops out of ...
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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UsedGood. Hardcover; fading and shelf wear to exterior; bumps to the lower corners; l ight fade spots to page edges; otherwise in good condition with clean text and tight binding.
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VERY GOOD. Near Fine. Very dark blue hardcover without dust jacket, volume 130 1965. Cover very lightly soiled from use; upper page edges a little dusty. Interior like new. No marks or writing. Nice condition. **We provide professional service and individual attention to your order, daily shipments, and sturdy packaging. FREE TRACKING ON ALL SHIPMENTS WITHIN USA.
