This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1887 Excerpt: ...together the decomposition is complete. Ag2 S + Cu Cl2 = 2 Ag CI + Cu S. When sub-chloride of copper and sulphide of silver are mixed, the following reaction takes place: Ag2 8 + Cu2 Cl2 = 2 Ag 01 + Cu2 S. When one hundred parts of the sulphide of silver are treated with sub-chloride, in a solution of salt, as much as ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1887 Excerpt: ...together the decomposition is complete. Ag2 S + Cu Cl2 = 2 Ag CI + Cu S. When sub-chloride of copper and sulphide of silver are mixed, the following reaction takes place: Ag2 8 + Cu2 Cl2 = 2 Ag 01 + Cu2 S. When one hundred parts of the sulphide of silver are treated with sub-chloride, in a solution of salt, as much as 7.6 or 8.3 per cent of the silver remains dissolved in the salt solution. When the residue was treated with zinc, the following reaction took place: Ag3 S + Cu2 Cl2 + Zn = Zn Cl2 + Cu2 S + 2 Ag. When a salted solution of sub-chloride of copper is mixed with a saturated solution of chloride of silver in salt, no precipitation takes place, nor can it reduce chloride of silver when it is in powder. If sulphide of silver is added to the salt solution of sub-chloride of copper, chloride of copper, sulphide of copper, and metallic silver are produced. Na CI, Cu, CL. +Ag2 S = Na CI, Cu Cl2 + Cu S + 2 Ag. It thus appears, that while it cannot affect the chloride of silver, the sub-chloride of copper can reduce sulphide of silver, which, in the presence of mercury, is amalgamated without having passed into the state of chloride at all. If ammonia is added to the solution of the sub-chloride of copper and chloride of silver, silver is precipitated. 2 AgCl + Cu2Cl2 + NH, = 2 Ag + 2 Cu CL + N Hs. When chloride of silver, sulphide of copper, and ammonia are heated, a blue solution is obtained. One half the chloride of silver is converted into sulphide of silver. The residue, which is black, is composed of sulphide and chloride of silver, and contains no copper. 8 AgCl + 2CuS = AgCl + 2 Ag, S + 3 AgCl + 2CuCl2. 'v ' y' Not Dissolved. Dissolved. Three parts of chloride of silver and two of chloride of copper remain in solution. If two parts of chloride of si...
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