This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1905 Excerpt: ...from left to right. Wa will then be 1 foot from L0 and (W+J'F2 +..+Wn) will be 103,000 pounds; (W3 + W4) will be either 10,000 or 30,000 pounds, and (TV+TV2) either 93,000 or 73,000 pounds. According to the criterion 103,000 must lie between the values of (--1.74X93,000) + (97.4X10,000) and (-1.74 X 73,000) + (97.4 X30 ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1905 Excerpt: ...from left to right. Wa will then be 1 foot from L0 and (W+J'F2 +..+Wn) will be 103,000 pounds; (W3 + W4) will be either 10,000 or 30,000 pounds, and (TV+TV2) either 93,000 or 73,000 pounds. According to the criterion 103,000 must lie between the values of (--1.74X93,000) + (97.4X10,000) and (-1.74 X 73,000) + (97.4 X30, ooo). Since it is so found, this position satisfies the conditions for greatest negative stress. In determining the value of that stress, it will be more simple to treat the external forces situated to the right of the section passed through the truss. The reaction at L8 is then and the negative weight at L2 is 3,200 pounds. Therefore UL2 =8,700X325-3,200X165---=-18,000 lbs. 123 Since this compressive stress is much less than the dead-load tensile stress, this panel needs no counterbracing. U2L3. In this member =225, m = $o, = 25, = 239, and l(m+i) l = 200. Hence----;--= 11.2, and--=0.80. pi i y Placing W3 at L3, there will be 29 feet of uniform load on the bridge, and (W+W2 +...+Wn) =284,000 + (29,200X2) = 342,000 lbs. Either 30,000 or 50,000 pounds may be considered in the panel. The criterion is therefore satisfied. The reaction at L0 becomes 1 f, . (29)2 X 2,000 200 I4'944'000 (284,000 X34) 4-J = 127,120 lbs. The negative weight at L2 is, as before, 9200 pounds. Taking moments about the intersection of the proper chord members, there is found U2L3 =(127,120 X225)-(9,200 X2 75) = + 109,000 lbs. The loads will be taken to advance from left to right for the greatest counter-stress, and W2 will be placed at L2. W10 is then 2 feet from L0. Then W +W. +... +Wn = 152,000, + W2 = 10,000 or 30,000, Wz + 14 = 142,000 or 122,000, and it will be found that the criterion is satisfied. The reaction at L8 becomes R = 4,637,000 + (152,000 ...
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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Seller's Description:
PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
