This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1890 Excerpt: ...to n, describe an arc; and from B as a centre, with a radius equal to m, describe an arc intersecting the former arc at C. Draw CA and CB. Then A CAB is the A required. Q.E. F Discussion, The problem is impossible when one side is equal to or greater than the sum of the other two. Ex. 111. The base, the altitude, and ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1890 Excerpt: ...to n, describe an arc; and from B as a centre, with a radius equal to m, describe an arc intersecting the former arc at C. Draw CA and CB. Then A CAB is the A required. Q.E. F Discussion, The problem is impossible when one side is equal to or greater than the sum of the other two. Ex. 111. The base, the altitude, and an angle at the base, of a triangle being given, to construct the triangle. Ex. 112. Show that the bisectors of the angles contained by the opposite sides (produced) of an inscribed quadrilateral intersect at right angles. Ex. 113. Given two perpendiculars, AB and CD, intersecting in O, and a straight line intersecting these perpendiculars in E and F; to construct a square, one of whose angles shall coincide with one of the right angles at O, and the vertex of the opposite angle of the square Bhall lie in EF. (Two solutions.) Proposition XXXIII. Problem. 283. Two sides of a triangle and the angle opposite one of them being given, to construct the triangle. Case I. If the side opposite to the given angle is less than the other given side. Let b be greater than a, and A the given angle. To construct the triangle. Construction. Construct Z DAE--to the given Z A. 276 On AD take AB = b. From B as a centre, with a radius equal to a, describe an arc intersecting the side AE at Cand C. Draw.BCand BC. Then both the A ABC and ABC.', D fulfil the conditions, and hence we have two constructions. This is / called the ambiguous case. y a Discussion. If the side a is equal-' to the J_ BS, the arc described from B will touch AE, and there will be but one construction, the right tri-angle ABS. a.---If the given side a is less than the / a _L from B, the arc described from B /-will not intersect or touch AE, and---hence the problem is impossible. If the Z ...
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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Seller's Description:
PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
Choose your shipping method in Checkout. Costs may vary based on destination.
Seller's Description:
PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.