This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1899 Excerpt: ...expressed, for if we lay the four radicles in diagram 1 (under) on a spiral in the order "R c x RV ten te uPPer half will form a right-handed, and the lower a lefthanded screw. If the compound contains an odd number of carbon atoms, then the bisecting line passes through the middle (non-asymmetric) one. The following ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1899 Excerpt: ...expressed, for if we lay the four radicles in diagram 1 (under) on a spiral in the order "R c x RV ten te uPPer half will form a right-handed, and the lower a lefthanded screw. If the compound contains an odd number of carbon atoms, then the bisecting line passes through the middle (non-asymmetric) one. The following diagrams represent inactive compounds: II. n=2. A. First class: N=a=4, i=0, r=2. Four active combinations are possible; two pairs of antipodes: Which of these configurations belongs to each isomer has not yet been determined. Other examples are: Phenyl-o-chlorolactic aeid. C6H3-CH.OH-CH.C1-COOH Phenyl-3-chlorolaotic acid. C H3-CH.C1-CH.OH-COOH Trioxybutyric acid.. CH.OH-CH.OH-CH.OH-COOH B. Second class: N=3, a=2, i = l, r=l. If B=B, then, of the combinations given under r2 A, 1 and 2 are identical, as can be seen by tumii: one of them upside down, and there remain: B. Third class: N=4, a=2, i=2, r=l. In the configurations given under A, the following are identical when B=Bl: the following of these sixteen active configuration; are known: B. Second class: N=10, a=8, i=2, r=4. This number of isomers can be ascertained by setting E=E1 in the configurations given under A, and we find that the following become identical: belong to this group, and of the latter all the ten forms are known: Omitting E and E, the following are the thirtytwo possible combinations: Only few substances are known which correspond to any of these configurations, and these are: B. Third class: N=16, a=12, i=4, r=6. When E=E, then, of the configurations given Tinder A, the following are identical: As the formula for the calculation of the number of possible isomers indicates, there are sixteen configurations left; namely, six active pairs and four inactive forms....
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