This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1910 Excerpt: ... solution to decolorize the alkaline solution containing the 0.5 gram of pure copper, and that 10 c.c. were required to decolorize the copper solution from 0.5 gram of copper ore, the amount of copper in the ore would be determined as follows: the number of cubic centimeters of potassium cyanide solution assumed as a ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1910 Excerpt: ... solution to decolorize the alkaline solution containing the 0.5 gram of pure copper, and that 10 c.c. were required to decolorize the copper solution from 0.5 gram of copper ore, the amount of copper in the ore would be determined as follows: the number of cubic centimeters of potassium cyanide solution assumed as a standard, viz., 35 c.c., bears the same relation to 100 per cent or the whole as the number of cubic centimeters used to decolorize the copper contained in the solution from 0.5 gram of copper ore bears to the total per cent of copper in that amount. The equation would read as follows: 35 c.c.: 100 per cent: 10 c.c.: x per cent, x per cent equalling 28.57, the percentage of copper in the 0.5 gram of ore. To simplify, this may be determined as follows: divide the number of cubic centimeters required to decolorize the copper solution from 0.5 gram of ore by the number of cubic centimeters that indicates the strength of the potassium cyanide, and the result would be the percentage of copper (1035 = 28.57). When the copper ore is not rich take from 2 to 4 grams, and divide the resulting percentage shown after titrating to reduce the result to the basis of 0.5 gram of ore, viz.: if 2 grams of ore were titrated, the 2 grams would be 4 times the 0.5 gram which represents the 100 per cent in making the standard, consequently the resulting percentage must be divided by 4 to give the true value. "E" To Make a Standard Solution.--Dissolve pound of chemically pure potassium cyanide in 1 gallon of distilled water. This solution should stand at least twenty-four hours before using, and should be kept in a dark bottle wrapped in paper, as exposure to the light weakens the strength. The strength of the solution is determined in the following ma...
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