This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1854 Excerpt: ...angle EFC is equal to ABC; therefore the sine of BC is to the radius as the sine of AC is to the sine of the angle ABC. In like manner it may be shown that the sine of BC is to the radius, as the sine of AB is to the sine of ACB. Cor. Let the angles of the triangle ABC righlangled at A, be denoted by A, B, C, and the ...
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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1854 Excerpt: ...angle EFC is equal to ABC; therefore the sine of BC is to the radius as the sine of AC is to the sine of the angle ABC. In like manner it may be shown that the sine of BC is to the radius, as the sine of AB is to the sine of ACB. Cor. Let the angles of the triangle ABC righlangled at A, be denoted by A, B, C, and the opposite sides (or the angles measured by them) by a, b, c, respectively; and let the corresponding parts of a triangle complemental to ABC, be denoted by A', B', C, a', b', c the angle A' being a right angle. Then (Art. 4), if B'=B; C=comp. 5, 5'=comp. C, a'=comp. c, c'= comp. a: and if C=C; B'=comp. c, c'=comp. B, a'= comp. b, J'=comp. a. Now by the preceding proposition, sin a: R:: sin b: sin B; hence if unity be put for R, (1) sin b=sin a sin B. Likewise, since the same equation holds good in the complemental triangles, sin 5'=sin a' sin B'; from which equation are derived the two following; one for the case in which B'=B, the other for that in which C'=C; sin comp. C=sin comp. c sin B, sin comp. a=sin comp. b sin comp. c; or (2) cos C=cos e sin B, (3) cos a=cos b cos c. 6. In a right-angled spherical triangle, the sine of either of the sides containing the right angle is to the radius as the tangent of the other of these sides is to the tangent of the opposite angle. Let ABC be a triangle right-angled at A, the sine of AC is to the radius as the tangent of AB is to the tangent of the opposite angle ACB. Let D be the center of the sphere; join DA, DB, DC, draw AE perpendicular to CD; and AF a tangent to AB, meeting DB produced in F; also draw EF; this will be perpendicular to CD. For since AF is a tangent to AB, it is perpendicular to AD; and being drawn in the plane BAD at right angles to AD the intersection of this plane with the plane CA..
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Like New. Used-Like New. This is a reproduction of an out of print title. This book may have occasional imperfections such as missing or blurred pages, poor pictures, errant marks, etc. that were either part of the original artifact, or were introduced by the scanning process. Ships from UK in 48 hours or less (usually same day). Your purchase helps support Sri Lankan Children's Charity 'The Rainbow Centre'. 100% money back guarantee. We are a world class secondhand bookstore based in Hertfordshire, United Kingdom and specialize in high quality textbooks across an enormous variety of subjects. We aim to provide a vast range of textbooks, rare and collectible books at a great price. Our donations to The Rainbow Centre have helped provide an education and a safe haven to hundreds of children who live in appalling conditions. We provide a 100% money back guarantee and are dedicated to providing our customers with the highest standards of service in the bookselling industry.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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New. Sewn binding. Cloth over boards. 126 p. In Stock. 100% Money Back Guarantee. Brand New, Perfect Condition, allow 4-14 business days for standard shipping. To Alaska, Hawaii, U.S. protectorate, P.O. box, and APO/FPO addresses allow 4-28 business days for Standard shipping. No expedited shipping. All orders placed with expedited shipping will be cancelled. Over 3, 000, 000 happy customers.
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PLEASE NOTE, WE DO NOT SHIP TO DENMARK. New Book. Shipped from UK in 4 to 14 days. Established seller since 2000. Please note we cannot offer an expedited shipping service from the UK.
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Good+ Original Black cloth binding. There is a small chip to the cloth both at the top and bottom of the spine. Aorners are bumped and slightly worn through. There is foxing to the pages. The text block is sound and the pages are free from tears or marking. A scarce antiquarian geometry and trigonometry book.; 122 pages.
